Retrieve every data from database without one field using rule

You can use the 'selection' parameter in the a!query() to pass all the other field names except status. 

I have added 'selection' paramater in the a!query. And also passed all fields excep status.

But it shows an error like in above template.

My Updated Code:

cast('type!{urn:com:appian:types:HSM}HSM_Elements?list',
a!queryEntity(
entity: cons!HSM_Entity,
query: a!query(
selection:a!querySelection(
Columns: a!queryColumn(
field:{"S_No","Employee_Name","Employee_Id","Employee_Email_Id","Query","Comments","Date"},
)
),
pagingInfo: a!pagingInfo(
startIndex: 1,
batchSize: 5000,
sort: a!sortInfo(
field:"S_No",
ascending: true,
)
)
)
).data
)

A queryColumn can only have one column name. And hence you will have to add multiple query columns. 
Check the code below..

cast('type!{urn:com:appian:types:HSM}HSM_Elements?list',
  a!queryEntity(
    entity: cons!HSM_Entity,
    query: a!query(
      selection:a!querySelection(
        columns: {
          a!queryColumn(
            field:"S_No",
          ),
          a!queryColumn(
            field:"Employee_Name",
          ),
          a!queryColumn(
            field:"Employee_Id",
          )
        }
      ),
      pagingInfo: a!pagingInfo(
        startIndex: 1,
        batchSize: 5000,
        sort: a!sortInfo(
          field:"S_No",
          ascending: true,
        )
      )
    )
  ).data
)

Thank You for your support Harshit.

It works.

You have to use selection concept for it. queryselection()

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You can use the 'selection' parameter in the a!query() to pass all the other field names except status.