I need to get that by using the for each function

Certified Senior Developer

Hi all,

{1,2,3,8,9,9,9,9,9,80,90,70}, {56,76,54,32}, {20,23,45,54,32,54}, {1,2,3,4,5,6,7}, {11,12,13,14,15,16,17,18}

Please suggest how do this using foreach function get output like this,


length of array 1 is 12
length of array 2 is 4
length of array 3 is 6
length of array 4 is 7
length of array 5 is 8


Thank You In Advance

  Discussion posts and replies are publicly visible

    1. Here's the approach I would take (to help you work it out for yourself):Treat each array as a single item in a new array (that is, your new array is a "list of lists")
    2. iterate over that new array using a!forEach()
    3. for each item in the array use the function that tells you how many items are in an array
  • 0
    Certified Associate Developer
    in reply to Stewart Burchell

    I tried this but appian doesn't consider multiple arrays in a single array as list of lists. Appian is considering it as a single list

  • 0
    Certified Associate Developer

    Appian will take this as a single list of integers. To achieve what you want, the best solution I can think of is making a map for all individual arrays and then iterating over it using the keys.

    a!localVariables(
      local!arrays: a!map(
        1: {1,2,3,8,9,9,9,9,9,80,90,70}, 
        2: {56,76,54,32}, 
        3: {20,23,45,54,32,54}, 
        4: {1,2,3,4,5,6,7}, 
        5: {11,12,13,14,15,16,17,18}
      ),
      a!forEach(
        items: a!keys(local!arrays),
        expression: "Length of array " & fv!index & " is " & length(local!arrays[fv!item])
      )
    )

  • An alternative approach is to use the merge() function to generate a "list of lists" and use the length() function (which ignores null values in its counts):

    a!localVariables(
      local!myArray: fn!merge(
        /*{ 1, 2, 3, 8, 9, 9, 9, 9, 9, 80, 90, 70 },*/
        /*{ 56, 76, 54, 32 },*/
        /*{ 20, 23, 45, 54, 32, 54 },*/
        /*{ 1, 2, 3, 4, 5, 6, 7 },*/
        /*{ 11, 12, 13, 14, 15, 16, 17, 18 }*/
        { 1, 56, 20, 1, 11 },
        { 2, 76, 23, 2, 12 },
        { 3, 54, 45, 4, 14 },
        { 8, 32, 54, 4, 14 },
        { 9, null, 32, 5, 15 },
        { 9, null, 54, 6, 16 },
        { 9, null, null, 7, 17 },
        { 9, null, null, null, 18 },
        { 9, null, null, null, null },
        { 80, null, null, null, null },
        { 90, null, null, null, null },
        { 70, null, null, null, null }
      ),
      a!forEach(
        items: local!myArray,
        expression: fn!length(fv!item)
      )
    )

  • 0
    Certified Associate Developer

    One more solution I found to this problem is using merge() function. The code is attached below.

    a!localVariables(
      local!arr: merge(
        { 1, 2, 3, 8, 9, 9, 9, 9, 9, 80, 90, 70 },
        { 56, 76, 54, 32 },
        { 20, 23, 45, 54, 32, 54 },
        { 1, 2, 3, 4, 5, 6, 7 },
        { 11, 12, 13, 14, 15, 16, 17, 18 }
      ),
      local!size: {
        a!forEach(
          items: local!arr[1],
          expression: a!localVariables(
            local!temp: fv!index,
            a!forEach(
              items: enumerate(length(local!arr)) + 1,
              expression: if(
                a!isNullOrEmpty(local!arr[fv!item][local!temp]),
                0,
                1
              )
            )
          )
        )
      },
      a!forEach(
        items: local!size,
        expression: "length of array " & fv!index & " is " & sum(fv!item)
      )
    )