Hi
In below query rule i am passing 2 and 3 product ids so it was returning both 2 and 3 product id's email id's but i want 2 product id email ids in one list and 3 product id email ids separately means like two list of usernames separately could you please suggest on this
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a!forEach( local!uniqueProductIds, a!map( productId: fv!item, emailIds: rule!getEmailIdsForProductId(id: fv!item) ) )
The above will result in a list of maps where each map contains the single product ID and any associated email IDs (you would need to fill in correct rule names/syntax/etc of course). The phrasing in your original post is pretty confusing and lacking in punctuation but I did my best to parse what you're actually after, but apologies if this is off base.