I was exploring more on the simple if() function. Ideally the function is writte

Hello George, this looks like an anomaly but it isn't. Below are few points to elaborate:
1. fn!if accepts an odd number of parameters greater than 3.
2. Condition need not be an equation (a>2) or if condition (isnull). Integer or text can also be provided in the place of condition. when integer is given as condition it returns 'valueIfTrue' and when text is given it returns 'valueIfFalse'. Eg. if(132, "a", "b") returns "a"; if("abc", "a", "b") returns b.
3. The exception to above rule is when you give condition like true, false, true(), false(), 1, and 0 (1 or 0 is translated as true or false respectively when Appian expects Boolean value)
4. When more than 3 odd number parameters are passed it converts your if condition into nested if. With brackets your expression looks like this.
fn!if( false(), true(), if(false(), 1, if(2, 1, 2)))

According to our rule described in point 2, your expression correctly returns second last parameter '1'. Try to change that parameter to "a" and test again. It would return "a".

Hope this puts some light and clarifies any doubt.

-Khalid Khan

Hello George, this looks like an anomaly but it isn't. Below are few points to elaborate:
1. fn!if accepts an odd number of parameters greater than 3.
2. Condition need not be an equation (a>2) or if condition (isnull). Integer or text can also be provided in the place of condition. when integer is given as condition it returns 'valueIfTrue' and when text is given it returns 'valueIfFalse'. Eg. if(132, "a", "b") returns "a"; if("abc", "a", "b") returns b.
3. The exception to above rule is when you give condition like true, false, true(), false(), 1, and 0 (1 or 0 is translated as true or false respectively when Appian expects Boolean value)
4. When more than 3 odd number parameters are passed it converts your if condition into nested if. With brackets your expression looks like this.
fn!if( false(), true(), if(false(), 1, if(2, 1, 2)))

According to our rule described in point 2, your expression correctly returns second last parameter '1'. Try to change that parameter to "a" and test again. It would return "a".

Hope this puts some light and clarifies any doubt.

-Khalid Khan