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how would I trim a mix of newline and space characters from the beginning and en
srinivasm
over 9 years ago
how would I trim a mix of newline and space characters from the beginning and end of a text string? For example,
"
this is
a string
" becomes
"this is
a string"
OriginalPostID-174728
OriginalPostID-174728
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Stewart Burchell
over 5 years ago
+1
Appian Employee
I would start by substituting all "new line" characters with a space; and then use trim() to remove all unnecessary spaces. So: fn!trim( fn!substitute( ri!myString, char( 10 ), " " ) …
Stewart Burchell
over 5 years ago
in reply to
Stewart Burchell
+1
Appian Employee
I just noticed the previous replies that reference use of char(13) alongside char(10)...so the principle remains the same, but you'd iterate over the string to substitute both with a space and then tidy…
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Dan Lluhi
Certified Lead Developer
over 9 years ago
@mschmitt nice catch on the newline. Your solution looks great, the only thing I can think of that could be might need to be tweaked is if @srinivasm needs to retain consecutive newlines in the middle of the string. Rejoining the split array on char(10) will only add single newlines, so something like
"a
b"
will change to
"a
b".
Also I believe joinarray ignores empty strings, so removing nulls may not be required.
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Dan Lluhi
Certified Lead Developer
over 9 years ago
@mschmitt nice catch on the newline. Your solution looks great, the only thing I can think of that could be might need to be tweaked is if @srinivasm needs to retain consecutive newlines in the middle of the string. Rejoining the split array on char(10) will only add single newlines, so something like
"a
b"
will change to
"a
b".
Also I believe joinarray ignores empty strings, so removing nulls may not be required.
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