This is a question about the behavior of fn!index() function. The syntax is fn!i

This is a question about the behavior of fn!index() function. The syntax is fn!index(array, indices, defaultValToReturn).
The defaultValToReturn is of AnyType. Documentation mentions that default value should be of the same type as array elements. I find the behavior of index function strange in the below case:
fn!index( {4,5,6}, 1000, {}) -- As expected it returns a empty list i.e List of Variant since array size is less than 1000.
Now try, fn!index( {4,5,6}, {1000}, {} ) - This returns 4 - the first element in the array. I did not expect this result.
Now try, fn!index( {4,5,6}, {1000}, null ) - This returns nothing as expected.

Why does it behave in such manner for case 2? It always returns the first element whenever a multiple indices are provided and the default value is also an empty list.
Also try: fn!index({4,5,6}, {2,1000}, {}) - this returns 5,4. The 4 is the first element of the array.
I...

OriginalPostID-184786

OriginalPostID-184786

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  • Chiming in to add that I just noticed this issue (in the case of "index({4, 5, 6}, {1000}, {})"), and it still seems to be unresolved as of Appian 18.2.  I had to work around it by making the default output to null() then removing nulls from the resulting array, which seems like kind of an unnecessary pain.

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  • Chiming in to add that I just noticed this issue (in the case of "index({4, 5, 6}, {1000}, {})"), and it still seems to be unresolved as of Appian 18.2.  I had to work around it by making the default output to null() then removing nulls from the resulting array, which seems like kind of an unnecessary pain.

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