I am making use of the following expression =regexmatch("((?=.*\\d)(?

bhanuprakashg over 11 years ago

I am making use of the following expression
=regexmatch("((?=.*\\d)(?=.*[a-z])(?=.*[A-Z])(?=.*[@#$%]).{6,})",ri!specifiedPassword)
to check whether the specified string contains atleast one lower case,one upper case, one numerical,one special character and has length of atleast 6 characters. Everything works fine except for one lower case and one upper case validations. The expression returns true for both "welcome@123" and "WELCOME@123"
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0 Eduardo Fuentes
Appian Employee
over 11 years ago

It seems the issue is the flag the author of this plug-in is passing in compile() method:

Pattern p = Pattern.compile(pattern, 34);

your expression works fine if the compiled with the default:

Pattern p = Pattern.compile(pattern);

if I modify the regexmatch() method to use no flag, it correctly returns "False" for "welcome@123" and "WELCOME@123" but will return true for "WeLCOME@123"
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0 Eduardo Fuentes
Appian Employee
over 11 years ago

I couldn't find what that 34 means though, it doesn't seem to be one of the constants within the Pattern class docs.oracle.com/.../Pattern.html, int)

You can adapt this plugin to use Pattern.compile(pattern) instead to be able to use it for your requirement
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