Is 2 operations within the same expression in a for each loop possible?

Not sure what you are looking for. Do you want to describe the problem you want to solve?

You can perform many operations within the same expression of a forEach loop.  Anything in particular you're having difficulty doing?

Hi sanjuktab2257 

"zip in python", so based on this i read about zip function in python

So, we have a similar function in Appian: merge()

And can you please explain your usecase.

Thank you Yashwanth Akula , that was helpful.

It seems like "merge" is only for lists. Do you know how to merge two dictionaries.

a!localVariables(
  local!var1: {"John": "A", "Sam": "B", "Rose": "C"},
  local!var2: {"Smith": 1, "Williams": 2, "Thompson": 3},
  a!forEach(items: merge(local!var1.value, local!var2.value),
  expression: concat(fv!item[1], " ,", fv!item[2])
)

hi sanjuktab2257 , see if this helps.

a!localVariables(
local!var1: { "John": "A", "Sam": "B", "Rose": "C" },
local!var2: { "Smith": 1, "Williams": 2, "Thompson": 3 },
local!var1Values: a!flatten(
a!forEach(
items: a!keys(local!var1),
expression: if(
fv!isLast,
stripwith(keyval(local!var1, fv!item, ":", ","), "]"),
keyval(local!var1, fv!item, ":", ",")
)
)
),
local!var2Values: a!flatten(
a!forEach(
items: a!keys(local!var2),
expression: if(
fv!isLast,
stripwith(keyval(local!var2, fv!item, ":", ","), "]"),
keyval(local!var2, fv!item, ":", ",")
)
)
),
merge(local!var1Values, local!var2Values)
)

Merge the keys first. Example:

a!localVariables(
  local!var1: { "John": "A", "Sam": "B", "Rose": "C" },
  local!var2: { "Smith": 1, "Williams": 2, "Thompson": 3 },
  a!forEach(
    items: merge(a!keys(local!var1), a!keys(local!var2)),
    expression: concat(
      local!var1[fv!item[1]],
      ",",
      local!var2[fv!item[2]],
    )
  )
)

Thank you Stefan Helzle