Is 2 operations within the same expression in a for each loop possible?

Hi sanjuktab2257 

"zip in python", so based on this i read about zip function in python

So, we have a similar function in Appian: merge()

And can you please explain your usecase.

Thank you Yashwanth Akula , that was helpful.

It seems like "merge" is only for lists. Do you know how to merge two dictionaries.

a!localVariables(
  local!var1: {"John": "A", "Sam": "B", "Rose": "C"},
  local!var2: {"Smith": 1, "Williams": 2, "Thompson": 3},
  a!forEach(items: merge(local!var1.value, local!var2.value),
  expression: concat(fv!item[1], " ,", fv!item[2])
)

hi sanjuktab2257 , see if this helps.

a!localVariables(
local!var1: { "John": "A", "Sam": "B", "Rose": "C" },
local!var2: { "Smith": 1, "Williams": 2, "Thompson": 3 },
local!var1Values: a!flatten(
a!forEach(
items: a!keys(local!var1),
expression: if(
fv!isLast,
stripwith(keyval(local!var1, fv!item, ":", ","), "]"),
keyval(local!var1, fv!item, ":", ",")
)
)
),
local!var2Values: a!flatten(
a!forEach(
items: a!keys(local!var2),
expression: if(
fv!isLast,
stripwith(keyval(local!var2, fv!item, ":", ","), "]"),
keyval(local!var2, fv!item, ":", ",")
)
)
),
merge(local!var1Values, local!var2Values)
)

Merge the keys first. Example:

a!localVariables(
  local!var1: { "John": "A", "Sam": "B", "Rose": "C" },
  local!var2: { "Smith": 1, "Williams": 2, "Thompson": 3 },
  a!forEach(
    items: merge(a!keys(local!var1), a!keys(local!var2)),
    expression: concat(
      local!var1[fv!item[1]],
      ",",
      local!var2[fv!item[2]],
    )
  )
)

Merge the keys first. Example:

a!localVariables(
  local!var1: { "John": "A", "Sam": "B", "Rose": "C" },
  local!var2: { "Smith": 1, "Williams": 2, "Thompson": 3 },
  a!forEach(
    items: merge(a!keys(local!var1), a!keys(local!var2)),
    expression: concat(
      local!var1[fv!item[1]],
      ",",
      local!var2[fv!item[2]],
    )
  )
)