Splitting an array

Question

Hi All, 
 Need some help with writing a logic. 
 I have an integer array {1,2,3,4,5,6,7,8,9,10,11,12}. 
 I want an output as three arrays {1,2,3,4,5}, {6,7,8,9,10}, {11,12} 
 Any function or quick work around to split an array by grouping first five elements in an array, next five elements in array and so on

TIA 
 Arun

Arthur Lyrio · Accepted Answer

This should do 
 Just change the local!inputArray and local!maximumPerArray for other results. 
 a!localVariables(
 local!inputArray: {1,2,3,4,5,6,7,8,9,10,11,12},
 local!totalArray: length(local!inputArray),
 local!maximumPerArray: 5,

 local!amountArrays: ceiling(local!totalArray / local!maximumPerArray),
 local!iterationArray: enumerate(local!amountArrays),

 a!forEach(
 items: local!iterationArray,
 expression: with(
 local!leftAmountToCut: fv!item * local!maximumPerArray,
 local!rightAmountToCut: local!totalArray - ((fv!item + 1) * local!maximumPerArray),
 
 rdrop(
 ldrop(
 local!inputArray,
 local!leftAmountToCut
 ),
 if(local!rightAmountToCut < 0, 0, local!rightAmountToCut)
 )
 )
 )
)

Stefan Helzle · Answer

May I ask why you need to do that? 
 
 Tried to reduce the lines of code a bit ... 
 a!localVariables(
 local!list: floor(rand(23)*100),
 local!max: 5,
 
 a!forEach(
 items: enumerate(ceiling(length(local!list) / local!max)),
 expression: a!forEach(
 items: fv!item * local!max + 1 + enumerate(local!max),
 expression: index(local!list, fv!item, {})
 )
 )
)

shukurs0001 · Answer

1) 
 a!forEach(
items: touniformstring(enumerate(200-100+1) + 100),
expression: if( find("5",fv!item), fv!item,{} )
) 
 2) 
 a!forEach(
 items: enumerate(5),
 expression: repeat(fv!item,fv!item)
)

siddharth_m · Answer

Does this help ? 
 a!localVariables(
 local!list: {
 {
 id: 1,
 text: "first text",
 name: "Ada"
 },
 {
 id: 2,
 text: "2nd text",
 name: "ben"
 },
 {
 id: 3,
 text: "3rd text",
 name: "sam"
 }
 },
 index(
 local!list,
 1 + enumerate(
 2/* the specific index value*/
 
 )
 )
)

Ujjwal Rathore · Answer

Here is the answer for 1 Question :- a!localVariables(
 local!xyz: 101 + enumerate(100),
 local!where_five: a!forEach(
 items: local!xyz,
 expression: like(tostring(fv!item), "*5*")
 ),
 index(
 local!xyz,
 wherecontains(true, local!where_five),
 {}
 )
) 
 Q2. 
 a!forEach(
 enumerate(5),
 substitute(
 tostring(
 repeat(fv!index,fv!item)
 ),
 "; ",
 ""
 )
)

samarm0001 · Answer

This works fine with just a single forEach().

Splitting an array

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