Could someone explain why the following code work without compiler errors?
if( isnull(ri!user), "", isusernametaken(ri!user), user(ri!user, "firstName") & " " & user(ri!user, "lastName"), joinarray(split(ri!user, "."), " ") )
I expect some kind of evaluation error, but it works just as the three lines starting on "isusernametaken" were an embedded if.
I saw that in one of the Appian courses and I'm wondering if it is some undocumented feature of the if function.
Thank you
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if() has hidden else if functionality in it. What's documented is:
if(
condition
return if true,
return if false
)
What you can do with it:
condition1,
return if condition1 true
condition2 if condition1 false {else if}
return if condition2 true
return if condition2 false
Or you can do it with 7, 9, 11, 13. Every odd input is another conditional until the very last one, what returns if they're ALL false.
It's way less keypresses, but gets dramatically unreadable.
Thank you Dave, understood!