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vijaykumars5676
vijaykumars5676
March 28, 2023
Question

Dictionary operations

  • March 28, 2023
  • 2 replies
  • 3 views

I have to local variables as input

1. List of dictionary : [ [ id:1,value:"abc" ] , [ id:2,value:"bbb" ] , [ id:4,value:"ccc" ] ]

2. List of integers: [1,4]

 I want to create 3rd local variable (List of values) by selection value from dictionary where id is present in the List of integers 

example : 

result ->    List of values : [ "abc","ccc" ]

    2 replies

    S
    sanchitg0002
    March 28, 2023

    a!localVariables(
  local!dict: {
    { id: 1, value: "abc" },
    { id: 2, value: "abcde" },
    { id: 3, value: "pww" }
  },
  local!intArr: { 1, 3 },
  index(
    local!dict.value,
    wherecontains(
      tointeger(local!intArr),
      tointeger(local!dict.id)
    ),
    null
  )
)

    subhad
    subhad
    Participating Frequently
    March 28, 2023

    Hi Vijaykumar,

    Try the below code,

    I would suggest you to go over the Appian functions which I have mentioned in the snippet

    a!localVariables(
local!list: {
{ id: 1, value: "abc" },
{ id: 2, value: "bbb" },
{ id: 4, value: "ccc" }
},
local!index: { 1, 4 },
index(
local!list.value,
wherecontains(local!index,tointeger(local!list.id)),
null
)

)

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