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H
herver5127
December 26, 2023
Question

How to use a!iconIndicator in a gridColumn(), the icon cannot display

  • December 26, 2023
  • 4 replies
  • 0 views

a!gridColumn( 
label: "Status", 
sortField: "status",
value: if (
fv!row.isTesting, 
    a!iconIndicator( icon: "STATUS_NOTDONE",
    ), 
    a!iconIndicator( icon: "STATUS_OK", 
    ), 
)

    4 replies

    H
    herver5127Author
    December 26, 2023

    I've solved myself the issue using a!imageField in the value

    venkatrea696188
    venkatrea696188
    December 27, 2023

    Or you can use "Richtext icon" it's easier .

      mikes0011
      mikes0011
      Brainy
      December 27, 2023

      completely agree with this - rich text icon is newer, better supported, has FAR more flexibility and MANY MANY more options.  i've been actively replacing uses of iconIndicator in my system for the past 3 straight years now due to how cumbersome the older way was.

      The Expression Guru
      sangeethab0005
      sangeethab0005
      December 27, 2023

      Hi [mention:60209c2a71304231ab861500c2c17107:e9ed411860ed4f2ba0265705b8793d05] ,

      a!gridColumn(
      label: "Status",
      sortField: "status",
      value: if (
      fv!row.isTesting,
      if(
      ri!showNext,
      a!imageField(
      images: a!documentImage(document: a!iconIndicator("STATUS_OK"))
      ),
      a!imageField(
      images: a!documentImage(document: a!iconIndicator("STATUS_OK"))
      )
      )
      )
      )

      Kindly try this

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