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shilpak8740
January 20, 2023
Question

logic Scenario

  • January 20, 2023
  • 3 replies
  • 0 views

lets say I had a word "Appian" 

now I need to covert into a list

expecting a result like below( Letter - (Number of times that particular letter is being repeated in the given word))

A-2

p-2

i-1

n-1

Please let me know logic to achieve this

    3 replies

    S
    surjitg0001
    January 20, 2023

    Try something like this.

    a!localVariables(
  local!input: "Appian",
  local!inputChars: char(code(local!input)),
  local!uniqueInputChars: union(local!inputChars, local!inputChars),
  a!forEach(
    local!uniqueInputChars,
    a!map(
      inputChar: fv!item,
      count: length(
        wherecontains(fv!item, local!inputChars)
      )
    )
  )
)

    H
    harshitham3563
    January 20, 2023

    Hi @shilpak8740, Please refer this code.

    a!localVariables(
local!name: upper("Appian"),
local!namearray: a!forEach(
items: enumerate(len(local!name)) + 1,
expression: local!name[fv!index]
),
local!union: union(local!namearray, local!namearray),
local!result: a!forEach(
items: local!union,
expression: {
fv!item & " - " & count(wherecontains(fv!item, local!namearray))
}
),
local!result
)

    harshitb6843
    harshitb6843
    January 20, 2023

    Already answered here - community.appian.com/.../how-to-iterate-through-a-string

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