Known Participant

Solved

Comparing two arrays

Forum|Forum|2 years ago
January 10, 2024
8 replies
9 views

Hi,

Is there any straightforward method to compare below two arrays in such a way that, SelectedAnswersArray[1]=correctAnswersArray[1] , SelectedAnswersArray[2]=correctAnswersArray[2] and SelectedAnswersArray[3]=correctAnswersArray[3] .

SelectedAnswersArray: {"a","c","b"}

correctAnswersArray: {"a","b","c"}

Best answer by harshitb6843

{"a","c","b"}={"a","b","c"}

As unreal as it looks, just an equal operator will work.

stefanhelzle0001

Brainy

Did you try a simple foreach() that compares the values on both lists by index? This will get you a list of booleans.

C

chithrav2030Author

Known Participant

Can we use foreach() inside a foreach() ?

stefanhelzle0001

Brainy

Sure, but why would you want to do that?

harshitb6843Answer

Brainy

{"a","c","b"}={"a","b","c"}

As unreal as it looks, just an equal operator will work.

C

chithrav2030Author

Known Participant

oh great... Will try this approach also...

M

mathurambm639546

Inspiring

Hi,
Adding to Harshit's and Stefan's comments, you can also use Appian's OOTB function 'exact', which will help you, in case you need to compare in a case-sensitive manner.

a!forEach(
  items: merge({ "a", "B", "C" }, { "a", "b", "C" }),
  expression: exact(fv!item[1], fv!item[2])
)

mathieud0001

Brainy

Comparing two arrays returns a list of booleans. This might be a little better:

a!localVariables(
  local!array1: { 1, 2, 3 },
  local!array2: { 1, 2, 3 },
  not(contains(local!array1 = local!array2, false))
)

rithanir5887

Participating Frequently

Hello [mention:effa9f429a764d98b42411e7f964ed12:e9ed411860ed4f2ba0265705b8793d05] ,

You can try this as well.

a!localVariables(
  local!arr1:{1,2,4},
  local!arr2:{1,2,3},
  a!forEach(
    items: local!arr1,
    expression:fv!item=local!arr2[fv!index]
  )
)

Sign up

Login with SSO

Login to the community

Login with SSO