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supriyam0001
supriyam0001
Participating Frequently
October 29, 2022
Solved

How to find out the number of vowels in a string in Appian ?

Hi,

Can anyone please let me know, how to find out the number of vowels in a string?

Thank you in advance

peter.lewis
peter.lewisAnswer
Employee
October 31, 2022

As you can see, there are a bunch of possibilities here, but honestly I think most of these overcomplicate it:

a!localVariables(
  local!text: "Test phrase with vowels",
  len(cleanwith(local!text, "aeiouAEIOU"))
)

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13 replies

ujjwalr0002
Participating Frequently
October 29, 2022

Hi, Check the below code

a!localVariables(
  local!text: "Television",
  local!vowels: { "a", "e", "i", "o", "U" },
  local!getVowels: a!forEach(
    items: char(code(local!text)),
    expression: if(
      contains(local!vowels, lower(fv!item)),
      fv!item,
      {}
    )
  ),
  length(local!getVowels)
)

    skk3042
    New Participant
    December 8, 2022

    Its not counting all the vowels, only first vowel is get counted

    mahesha928463
    Known Participant
    October 29, 2022

      stefanhelzle0001
      stefanhelzle0001
      Brainy
      October 29, 2022

      As I try to not solve every problem using a loop, here my solution:

      a!localVariables(
  local!text: "Television",
  local!vowels: { "a", "e", "i", "o", "u" },
  count(
    union(
      intersection(
        code(lower(local!text)),
        code(local!vowels)
      ),
      tointeger({})
    )
  )
)

        peter.lewis
        peter.lewisAnswer
        Employee
        October 31, 2022

        As you can see, there are a bunch of possibilities here, but honestly I think most of these overcomplicate it:

        a!localVariables(
  local!text: "Test phrase with vowels",
  len(cleanwith(local!text, "aeiouAEIOU"))
)

          stefanhelzle0001
          stefanhelzle0001
          Brainy
          October 31, 2022

          Genius !

          shukurs0001
          shukurs0001
          Known Participant
          December 12, 2022

          a!localVariables(
  local!string: "APPIAN",
  local!vowels: {"A","E","I","O","U"},
  length(wherecontains(local!vowels,char(code(local!string))))
)

            ankits7238
            New Participant
            February 24, 2024

            a!localVariables(
            local!string: "APPIAN NAME",
            local!code: char(code(local!string)),
            local!tip: cleanwith(local!code,"aeiouAEIOU"),
            a!forEach(
            items: local!tip,
            expression: a!localVariables(
            concat("on " & fv!index & " index- " & local!tip[fv!index])
            )
            )
            )

            davidj137213
            davidj137213
            Brainy
            February 24, 2024

            Use regular expressions function 

            community.appian.com/.../regular-expression-functions

            regexallmatches(
            "[aeiouAEIOU]",
            "SIMPLE TEST")

            bk8577
            New Participant
            August 16, 2026

            For more interesting Appian Coding Questions , you check this site : https://appianverse.com/coding

            rishikeshr4182
            rishikeshr4182
            Inspiring
            August 17, 2026

            Hi ​@supriyam0001, Try this

            if(
              a!isNullOrEmpty(ri!text),
              0,
              length(regexallmatches("(?i)[aeiou]", ri!text))
            )

             

            Rishikesh
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