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michaell0010
michaell0010
April 19, 2022
Solved

How to send user to a form when button is clicked

  • April 19, 2022
  • 7 replies
  • 0 views

I have a very simple app so far. There's no database or external process.  Just a few interfaces, with one that shows the content of a folder, given a folder ID.  I added a button to that interface that should send the user to a form where more files can be uploaded to the folder.  I created the below process model, which I'm calling with the below code. When I execute this code, the process stopped at the Document Upload without showing the actual interface.  No errors popped up either.  What am I doing wrong?

a!buttonWidget(
  label: "Add Documents",
  icon: "plus",
  saveInto: {
    folderId: ri!folderId,
    a!startProcessLink(
      processModel: cons!DSU_PM_DOCUMENT_UPLOAD,
    )
  },
  style: "PRIMARY",
)

 

    Best answer by stefanhelzle0001

    You cannot put a link into a button. Did you try to go through the basic tutorials?

    docs.appian.com/.../Tutorials.html

    7 replies

    richardm900458
    richardm900458
    April 19, 2022

    Hello michael,
    is your assignment fine?
    If yes, do you have tasks?
    Why do you try to archive that with a "startprocesslink" and not via submiting with a follow up form in the original process?

    michaell0010
    michaell0010Author
    April 19, 2022

    Excellent question, Richard! There's no "original process" in this case. It's just an interface with the button.  But your question is very relevant to my current situation, as I modified the startProcessLink to add the parameters expected by the process model. But I'm currently getting an error.  It all takes me to the starting point, which is to configure that button/startProcessLink correctly in the first place.  Below is the error I'm getting as well as the updated buttonWidget. Another key detail is that the error is preventing me from entering the process.

    a!buttonWidget(
  label: "Add Documents",
  icon: "plus",
  saveInto: {
    a!startProcessLink(
      processModel: cons!DSU_PM_DOCUMENT_UPLOAD,
      processParameters: {
        cancel: ri!cancel,
        folderId: 122184,
        uploadedFiles: ri!uploadedFiles
      }
    )
  },
  style: "PRIMARY"
)

    stefanhelzle0001
    stefanhelzle0001Answer
    Brainy
    April 19, 2022

    You cannot put a link into a button. Did you try to go through the basic tutorials?

    docs.appian.com/.../Tutorials.html

      mikes0011
      mikes0011
      Brainy
      April 19, 2022

      You need to have Activity Chaining enabled from the Start Node to the User Input Task in order for the user to be actually taken to the task when they click the Start Process Link.

      The Expression Guru
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