a!queryRecordType. Parameter "fields"

Question

I have the local variable called "encargo" to get a single record from a RecordType filtering by an id key. I want to get all the fields of the record type. Is there any way to tell it to the "fields" parameter or have I to list all of them instead?:

local!encargo: a!queryRecordType(
recordType: 'recordType!{47dcd902-6450-48f5-944d-06c0f19d2df1}Encargo DSAppian',
fields: {
'recordType!{47dcd902-6450-48f5-944d-06c0f19d2df1}Encargo DSAppian.fields.{85cdc5be-fc56-425c-9ec2-f9e617124992}id',
'recordType!{47dcd902-6450-48f5-944d-06c0f19d2df1}Encargo DSAppian.fields.{48d20aa7-6bfb-42ac-9ea0-0396fafa7ffd}fechasolicitud'
filters: a!queryFilter(
field: 'recordType!{47dcd902-6450-48f5-944d-06c0f19d2df1}Encargo DSAppian.fields.{85cdc5be-fc56-425c-9ec2-f9e617124992}id',
operator: "=",
value: ri!id
),
pagingInfo: a!pagingInfo(startIndex: 1, batchSize: 1)
).data

Thanks!

mikes0011 · Accepted Answer

AFAIK when no "fields" parameter is provided, the query automatically returns all fields that directly belong to that record type.  I just double-checked in my 25.1 environment and this behavior seems accurate.

harshm4411 · Answer

Hi [mention:8cdd6119fd07485ea8670348a7dd2045:e9ed411860ed4f2ba0265705b8793d05] ,If you want to retrieve all record fields, simply leave the fields parameter empty. By default, it will return all available record fields.

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