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eyleenm420293
eyleenm420293
June 10, 2024
Question

Create a link to start a process or record action

  • June 10, 2024
  • 7 replies
  • 0 views

Hi, 

I'm looking for a way to start a process by a given url, the process is now in a record action, in any case I can start it as process model, without any record action's relation because of I can send parameters to the process model. Any idea how to build this url?

Thanks in advance

7 replies

stefanhelzle0001
stefanhelzle0001
June 10, 2024

Appian does not support starting a process by a link.

Can you explain why you do not want to use the existing Appian features?

eyleenm420293
eyleenm420293Author
June 10, 2024

Thanks, but I think I got tha answer: 

local!actionUrlPart: "/actions/ActionId",
local!urlForRecord: a!urlForRecord(
recordType: recordType!XXX
targetLocation: site!SiteName.Page,
identifier: 1
),
local!urlFinal: replace(
local!urlForRecord,
search("/summary",local!urlForRecord,1),
8,
local!actionUrlPart
),

    priyankap3485
    priyankap3485
    July 24, 2024

    Hi [mention:11440e5cddbc4099be9301338785296f:e9ed411860ed4f2ba0265705b8793d05] ,

    I am working on similar requirement, may I know how do you find the local!actionUrlPart for the higher environment. specifically when you do not have access to this related action due to action security in records.

    TIA.

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