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zohaiba6627
zohaiba6627
March 11, 2024
Solved

Create Hyperlink to a Record View Page of Another Appian Application

  • March 11, 2024
  • 9 replies
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I am creating an Appian Application that has Data Model based on CDTs (SQL Server Tables and Views).

For the Record List Page, I have created Record Type from the CDTs which is sourced from a SQL Server View. The main ID on the list page is hyperlinked to navigate user to the Record View Page of the record in the same Appian Application.

However, I have a second column in the Record List Page, which contains the ID of a Record List View Item from another Application. I want this ID Hyperlinked as well, which navigates the user to Record View Page of another Appian Application through this Hyperlinked ID.

On the backend, I have simply created a Database View in SQL Server which contains ID of of both record item i.e. the individual record in the new application and the existing record in the old application. But on the front-end, I am not able to discover a way through which I can hyperlink the ID in the second column which navigates user to the Record View of the other application. 

Is there anyway through which I can handle this? Thank you in advance.

Best answer by venkatrea696188

a!Recordlink(), pass the record type and it's identifier

how I can access the RecordType of another application

Just Reference it recortype!XYZ_record , are you facing any issue?? 

9 replies

venkatrea696188
venkatrea696188
March 12, 2024

As long as you have access to the second application , you can use it as you want. Did you have access to second application? Access means Security are you part of second records security??

zohaiba6627
zohaiba6627Author
March 12, 2024

Yes, I have the access to the second application. I am not aware how I can access the RecordType of another application into the current application.

Or otherwise, what function would return the hyperlink to Record View of another application if I pass only just the Primary Key of the Record List Item?

venkatrea696188
venkatrea696188Answer
March 12, 2024

a!Recordlink(), pass the record type and it's identifier

how I can access the RecordType of another application

Just Reference it recortype!XYZ_record , are you facing any issue?? 

    prakhars0731
    prakhars0731
    March 12, 2024

    yes you can handle it by using records security

    zohaiba6627
    zohaiba6627Author
    March 12, 2024

    Yes, I have the access to the second application. I am not aware how I can access the RecordType of another application into the current application.

    Or otherwise, what function would return the hyperlink to Record View of another application if I pass only just the Primary Key of the Record List Item?

    karumurua531442
    karumurua531442
    March 12, 2024

    if you are having permissions for second record you can do it 

    zohaiba6627
    zohaiba6627Author
    March 12, 2024

    Yes, I have the access to the second application. I am not aware how I can access the RecordType of another application into the current application.

    Or otherwise, what function would return the hyperlink to Record View of another application if I pass only just the Primary Key of the Record List Item?

    harshitb6843
    harshitb6843
    March 12, 2024

    use a!richTextDisplayField with richTextItem() and configure its link property with a!recordLink() where you pass the record and the ID. Did you try this? What problems are you facing? 

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