Update a field based on indexing

Question

I have two variables of list type, 
local!selecteddata: { id:1, name:test1, id:4,name:test4}.  
local!data:{id:1,name:test1,
                 id:2,name:test2,
                 id2,name:test3,
                 id4,name:test4
}

if I update the "name" fields of local!selecteddata,How do I index local!data and update the field "name" for ids : 1 and 4 . Any help is appreciated

venkatrea696188 · Accepted Answer

Wrap it inside tointeger() and isn't it in reverse?? You want to update local!X  and update why you are giving direct record field reference??a!update(local!X[record.name],wherecontains(tointeger(local!Y.id),tointeger(local!X[recordname.id])),local!Y.name)

venkatrea696188 · Answer

a!localVariables(
  local!Y: {
    a!map(id: 1, name: "test5"),
    a!map(id: 4, name: "test6")
  },
  local!X: {
    a!map(id: 1, name: "test1"),
    a!map(id: 2, name: "test2"),
    a!map(id: 3, name: "test3"),
    a!map(id: 4, name: "test4")
  },
  a!update(
    local!X,
    wherecontains(local!Y.id, local!X.id),
    local!Y
  )
)

-------------------------------------------------------------

a!localVariables(
  local!Y: {
    a!map(id: 1, name: "test7"),
    a!map(id: 4, name: "test8")
  },
  local!X: {
    a!map(id: 1, name: "test1"),
    a!map(id: 2, name: "test2"),
    a!map(id: 3, name: "test3"),
    a!map(id: 4, name: "test4")
  },
  a!update(
    local!X,
    "name",
    a!update(
      local!X.name,
      wherecontains(local!Y.id, local!X.id),
      local!Y.name
    )
  )
)

It can be achieved multiple ways. use Wherecontains() to index based on id

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