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sanjuktab2257
sanjuktab2257
May 2, 2025
Question

Is 2 operations within the same expression in a for each loop possible?

  • May 2, 2025
  • 7 replies
  • 0 views

Can we perform 2 operations within the same expression of a forEach loop possible? (Ex: zip in python.)

7 replies

stefanhelzle0001
stefanhelzle0001
May 2, 2025

Not sure what you are looking for. Do you want to describe the problem you want to solve?

Z
zakarym8213
May 2, 2025

You can perform many operations within the same expression of a forEach loop.  Anything in particular you're having difficulty doing?

yashwantha0914
yashwantha0914
May 2, 2025

Hi [mention:9ce4b939559d45dc807b9271b84c0a9b:e9ed411860ed4f2ba0265705b8793d05] 

"zip in python", so based on this i read about zip function in python

So, we have a similar function in Appian: merge()

And can you please explain your usecase.

    sanjuktab2257
    sanjuktab2257Author
    May 5, 2025

    Thank you [mention:f0523105fd4d4e879f169a28f3dd0ec5:e9ed411860ed4f2ba0265705b8793d05] , that was helpful.

    It seems like "merge" is only for lists. Do you know how to merge two dictionaries.

    a!localVariables(
  local!var1: {"John": "A", "Sam": "B", "Rose": "C"},
  local!var2: {"Smith": 1, "Williams": 2, "Thompson": 3},
  a!forEach(items: merge(local!var1.value, local!var2.value),
  expression: concat(fv!item[1], " ,", fv!item[2])
)

    the expected output should be: "A ,1", "B, 2", "C, 3"

    R
    ravis0014
    May 6, 2025

    hi [mention:9ce4b939559d45dc807b9271b84c0a9b:e9ed411860ed4f2ba0265705b8793d05] , see if this helps.

    a!localVariables(
    local!var1: { "John": "A", "Sam": "B", "Rose": "C" },
    local!var2: { "Smith": 1, "Williams": 2, "Thompson": 3 },
    local!var1Values: a!flatten(
    a!forEach(
    items: a!keys(local!var1),
    expression: if(
    fv!isLast,
    stripwith(keyval(local!var1, fv!item, ":", ","), "]"),
    keyval(local!var1, fv!item, ":", ",")
    )
    )
    ),
    local!var2Values: a!flatten(
    a!forEach(
    items: a!keys(local!var2),
    expression: if(
    fv!isLast,
    stripwith(keyval(local!var2, fv!item, ":", ","), "]"),
    keyval(local!var2, fv!item, ":", ",")
    )
    )
    ),
    merge(local!var1Values, local!var2Values)
    )

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