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alim9650
Inspiring
October 4, 2022
Solved

using if statements in interface

Hi all, 

I'm creating an interface that records and calculates the working hours for employees, the idea is if the working hours are less than 8 it should display: " Working hours are incomplete " , and if it was less than 0 it should display: " insert your working hours correctly please " 

I made this expression, but when the value is less than 8 even it was less than 0 it always display : " Working hours are incomplete " 

here's the expression: 

{
a!richTextItem(
if(
ri!WorkingHours = "8",
"Working hours are complete",
if(
8 > ri!WorkingHours > 0,
"Working hours are not complete",
if(
ri!WorkingHours < 0,
"insert working hours correctly please"
)
)
)
)

harshitb6843
harshitb6843Answer
Brainy
October 4, 2022

Multiple conditions in Appian can be configured using or() & and() functions. 

a!richTextDisplayField(
  value: {
    a!richTextItem(
      if(
        ri!WorkingHours = "8",
        "Working hours are complete",
        if(
          and(8 > ri!WorkingHours, ri!WorkingHours > 0),
          "Working hours are not complete",
          if(
            ri!WorkingHours < 0,
            "insert working hours correctly please",
            {}
          )
        )
      )
    )
  }
)

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15 replies

harshitb6843
harshitb6843Answer
Brainy
October 4, 2022

Multiple conditions in Appian can be configured using or() & and() functions. 

a!richTextDisplayField(
  value: {
    a!richTextItem(
      if(
        ri!WorkingHours = "8",
        "Working hours are complete",
        if(
          and(8 > ri!WorkingHours, ri!WorkingHours > 0),
          "Working hours are not complete",
          if(
            ri!WorkingHours < 0,
            "insert working hours correctly please",
            {}
          )
        )
      )
    )
  }
)

    alim9650Author
    Inspiring
    October 4, 2022

    Thanks for your help, but when I tried the code I got this: Could not display interface. Please check definition and inputs. Interface Definition: Expression evaluation error at function 'if' [line 64]: Invalid number of parameters, function 'if' a minimum of 3 parameters (condition,true,false), passed 2.

      amans0009
      amans0009
      Participating Frequently
      October 4, 2022

      try this

      a!richTextDisplayField(
  value: {
    a!richTextItem(
      if(
        ri!WorkingHours = "8",
        "Working hours are complete",
        if(
          and(8 > ri!WorkingHours, ri!WorkingHours > 0),
          "Working hours are not complete",
          "insert working hours correctly please"
    
        )
      )
    )
  }
)
       

        ujjwalr0002
        Participating Frequently
        October 4, 2022

        Using the amazing match function.

        a!richTextDisplayField(
  value: {
    a!richTextItem(
      a!match(
        value: ri!WorkingHours,
        equals: 8,
        then: "Working Hours are complete",
        whenTrue: and(ri!WorkingHours > 0, 8 > ri!WorkingHours),
        then: "Working hours are not complete",
        default: "insert working hours correctly please"
      )
    )
  }
)

          alim9650Author
          Inspiring
          October 4, 2022

          it just show the default message even when the user inserts 8, or 4

          ujjwalr0002
          Participating Frequently
          October 4, 2022

          workings hours as 8 

          working hours as 4 

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